How do you solve $4(u+1)^2=18$ ?

Question

2213 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-22T14:37:39

$u= -1+-(3sqrt(2))/2$

$4(u+1)^2=18larr$ Divide both sides by 4

$(u+1)^2=18/4 larr$ Square root both sides

$u+1=+-sqrt(18/4)larr$ Subtract 1 from both sides

$u=+-sqrt(18/4)-1larr$ simplify the square root

$u=-1+-sqrt(2xx3^2)/sqrt(2^2)larr$

$u= -1+-(3sqrt(2))/2$

How do you solve 4(u+1)^2=184(u+1)^2=18?