How do you solve #4(x+1)^2=100#?
1 Answer
Explanation:
The key to this problem is the fact that for a given number
#a^2 = a * a" "# and#" "a^2 = (-a) * (-a)#
so right from the start you know that you're looking for two values of
#color(purple)(|bar(ul(color(white)(a/a)color(black)(sqrt(a^2) = |a| = {(+ a, " for "a >=0), (-a, " for "a < 0):})color(white)(a/a)|)))#
The first thing to do here is divide both sides of the equation by
#(color(red)(cancel(color(black)(4))) * (x+1)^2)/color(red)(cancel(color(black)(4))) = 100/4#
#(x+1)^2 = 25#
If you take the square root of both sides of the equation
#sqrt((x+1)^2) = sqrt(25)#
you will end up with
#(x+1) = + 5" "# or#" "(x+1) = -5#
This will get you
#x+1 = 5 implies x= 4" "# or#" " x+1 = -5 implies x= -6#
Therefore, the original equation has two possible solutions
#x = 4" "# or#" "x = -6#
Do a quick check to make sure that the calculations are correct
#x = 4:" " 4 * (4 + 1)^2 = 100#
#4 * 5^2 = 100" "color(green)(sqrt())#
#x = -6:" " 4 * (-6 + 1)^2 = 100#
#4 * (-5)^2 = 100" "color(green)(sqrt())#