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How do you solve $\frac{4}{x - 3} = 4$ $4/(x-3)=4$ ?

1 Answer

Feb 10, 2015

You can start by dividing both sides by $4$ $4$

$\frac{4}{x - 3} = 4 \to \frac{1}{x - 3} = 1$ $4/(x-3)=4->1/(x-3)=1$

$\to x - 3 = 1 \to x = 4$ $->x-3=1->x=4$

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