How do you solve 4x(x−18)=−288?
1 Answer
Sep 26, 2016
Explanation:
The difference of squares identity can be written:
a2−b2=(a−b)(a+b)
We use this later with
First note that both sides are divisible by
x(x−18)=−72
Multiply out the left hand side and add
0=x2−18x+72
0=x2−18x+81−9
0=(x−9)2−32
0=((x−9)−3)((x−9)+3)
0=(x−12)(x−6)
Hence:
x=12 orx=6