How do you solve $4c-4<8c-16<6c-6$ ?

Question

2611 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-28T19:37:06

$3 < c < 5$

$4c - 4 < 8c - 16 < 6c - 6$

separate into two inequalities:

$4c - 4 < 8c - 16$
$8c - 16 < 6c - 6$

solving $4c - 4 < 8c - 16$ :

$-4 < 4c - 16$

$12 < 4c$

$3 < c$

solving $8c - 16 < 6c - 6$ :

$8c < 6c + 10$

$2c < 10$

$c < 5$

now we have $3 < c$ and $c < 5$

giving $3 < c < 5$ .

How do you solve 4c-4<8c-16<6c-64c-4<8c-16<6c-6?