How do you solve #4d + 2(d - 1) = 22#?

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Answer 1 · 2018-03-20T21:32:47

#d=4#

We can start by distributing the #2# to the terms in parenthesis. We get:

#4d+2d-2=22#

We can further simplify the terms on the left to get:

#6d-2=22#

Adding #2# to both sides, we have:

#6d=24#

Finally, we can divide both sides by #6# to get:

#d=4#