How do you solve $4 ln (- x) + 3 = 21$ $4ln(-x)+3=21$ and find any extraneous solutions?

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How do you solve $4 ln (- x) + 3 = 21$ $4ln(-x)+3=21$ and find any extraneous solutions?

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Answer 1 · 2016-07-31T21:40:09

I found: $x = - 90.0171$ $x=-90.0171$

Explanation:

We can rearrange our expression:
$4 ln (- x) = 21 - 3$ $4ln(-x)=21-3$
$4 ln (- x) = 18$ $4ln(-x)=18$
$ln (- x) = \frac{18}{4} = 4.5$ $ln(-x)=18/4=4.5$
We use the definition of (natural) log to get:
$- x = e^{4.5}$ $-x=e^(4.5)$
And:
$x = - 90.0171$ $x=-90.0171$

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How do you solve $4 ln (- x) + 3 = 21$ $4ln(-x)+3=21$ and find any extraneous solutions?

1 Answer

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How do you solve $4 ln (- x) + 3 = 21$ $4ln(-x)+3=21$ and find any extraneous solutions?