How do you solve $4t + 1/3 = t + 5/6 + t - 3/6$ ?

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Answer 1 · 2016-04-15T13:57:28

$t = 0$

$color(blue)(4t) + 1 /3 =color(blue)(t) + 5/6 +color(blue)(t) - 3/6$

$color(blue)(4t - t -t )= 5/6 - 3/6 - 1 /3$

$color(blue)(4t - 2t )= 5/6 - 3/6 - 1 /3$

$2t = 5/6 - 3/6 - 1 /3$

The L.C.M of the denominators $( 6 ,6$ and $3)$ of the L.H.S $=6$

$2t = 5/6 - 3/6 - (1 *2 ) /(3 *2 )$

$2t = 5/6 - 3/6 - (2 ) /(6 )$

$2t = (5 -3 -2 ) /6$

$2t = (5 -5 ) /6$

$2t = (0) /6$

$2t = 0$

$t = 0 / 2$

$t = 0$

How do you solve 4t + 1/3 = t + 5/6 + t - 3/64t + 1/3 = t + 5/6 + t - 3/6?