How do you solve $4x²-1=0$ ?

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Answer 1 · 2016-09-03T11:10:22

1 or -1

$(2x-1)(2x+1)=0$
$2x-1=0,2x+1=0$
$2x=0+1,2x=0-1$
$2x=1,2x=-1$
$x=1/2,x=-1/2$
$S.S{+1/2,-1/2}$

Answer 2 · 2016-09-03T11:27:35

$x=+-1/2$

$color(green)("You only need to solve as a quadratic if you have a "bx)$ $color(green)("term in the standard form of "y=ax^2+bx+c)$

Given: $" "4x^2-1=0$

Add 1 to both sides

$4x^2=1$

Divide both sides by 4

$x^2=1/4$

Square root both sides

$x=+-sqrt(1/4) = +-1/2$

How do you solve 4x²-1=04x²-1=0?