Question

How do you solve `(4x-1)^2= 16`?

Answer 1

`x=-3/4` and `x=5/4`

Explanation:

Take the square root of both sides

`sqrt((4x-1)^2)=+-sqrt(16)`

`4x-1=+-4`

So we need to solve

`4x-1=4` and `4x-1=-4`

`4x=5`

`x=5/4`

`4x=-3`

`x=-3/4`