How do you solve (4x+1)(2x-7) =0? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Konstantinos Michailidis Sep 22, 2015 Refer to explanation Explanation: When you have a*b=0 then a=0 or b=0 hence we have that (4x+1)*(2x-7)=0=>4x+1=0 or 2x-7=0=>x=-1/4 or x=7/2 Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve -3x^2+12x+1=0? How do you solve -4x^2+4x=9? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation 81x^2+1=0? How do you solve -4x^2+4000x=0? How do you solve for x in x^2-6x+4=0? How do you solve x^2-6x-16=0 by factoring? How do you solve by factoring and using the principle of zero products x^2 + 7x + 6 = 0? How do you solve x^2=2x? See all questions in Comparing Methods for Solving Quadratics Impact of this question 4110 views around the world You can reuse this answer Creative Commons License