How do you solve $4x^2-14x-8=0$ ?

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Answer 1 · 2015-07-08T09:32:20

The solutions for the equation are
$color(blue)(x=4, x=-1/2$

$4x^2 -14x -8 = 0$

We can first factorise the equation and then find the solutions :

Factorising by splitting the middle term:

$4x^2 -14x -8 = 0$

$4x^2 + color(blue)(2x -16x) -2 = 0$

$2x (2x+1) -8 (2x+1) = 0$

$color(blue)((2x -8)(2x+1) = 0$

Now, equating the factors with zero to obtain the solutions
$2x -8 = 0 , color(blue)(x=8/2 = 4$
$2x+1 = 0 ,color(blue)( x =-1/2$

How do you solve 4x^2-14x-8=04x^2-14x-8=0?