Question

How do you solve `4x^2=28`?

Answer 1

`x^2=7` or `x=sqrt7`

Explanation:

Divide both sides by 4 (first step):

`x^2=28/4`
`x^2=7`

Take square root (of both sides):
`x=sqrt7`

This is your answer: `x=sqrt7`

Answer 2

`x=+-sqrt7`

Explanation:

`color(blue)"Isolate " x^2" by dividing both sides by 4"`

`(cancel(4) x^2)/cancel(4)=28/4`

`rArrx^2=7`

`color(blue)"take the square root of both sides"` remembering that the square root of a number can have a positive/negative value.

`sqrt(x^2)=color(red)(+-)sqrt7`

`rArrx=color(red)(+-)sqrt7`