How do you solve $4x^2 + 2x - 1 = 0$ by completing the square?

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Answer 1 · 2018-05-24T18:18:04

$x=(sqrt(5)-1)/4$ or $x=-(sqrt(5)+1)/4$

Dividing by $4$ we get
$x^2+1/2x-1/4=0$
completing the square
$(x+1/4)^2=5/16$
with the solutions above

How do you solve 4x^2 + 2x - 1 = 0 4x^2 + 2x - 1 = 0 by completing the square?