How do you solve $4x^2-4x=0$ ?

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Answer 1 · 2015-09-29T12:26:46

The solutions are
$color(blue)(x=0,x=1$

$4x^2−4x=0$

Both the above terms have $4x$ in common:

$4x^2−4x=color(blue)((4x)(x-1)$

Equating the factors to zero we obtain the solutions:

$4x=0, color(blue)(x=0$

$x-1=0, color(blue)(x=1$

How do you solve 4x^2-4x=04x^2-4x=0?