How do you solve $4 x^{2} - 4 x - 3 = 0$ $4x^2- 4x - 3=0$ ?

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How do you solve $4 x^{2} - 4 x - 3 = 0$ $4x^2- 4x - 3=0$ ?

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Answer 1 · 2015-12-23T15:11:30

Find factors of a and c that combine to give b, In this case
$(2 x + 1) (2 x - 3) = 0$ $(2x + 1)(2x - 3) = 0$

Explanation:

$a x^{2} + b x + c = 0$ $ax^2 +bx + c = 0$
Find factors of a and c that combine to give b, In this case
$a = 2 \cdot 2$ $a = 2*2$
$c = 1 \cdot (- 3)$ $c = 1*(-3)$
$b = 2 \cdot 1 + 2 \cdot (- 3)$ $b = 2*1 + 2*(-3)$
$(2 x + 1) (2 x - 3) = 0$ $(2x + 1)(2x - 3) = 0$

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How do you solve $4 x^{2} - 4 x - 3 = 0$ $4x^2- 4x - 3=0$ ?

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How do you solve $4 x^{2} - 4 x - 3 = 0$ $4x^2- 4x - 3=0$ ?