How do you solve $4x² = 2 – 7x$ ?

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Answer 1 · 2016-04-24T07:32:03

The solutions are:
$x= (-7+sqrt(17))/8$
$x= (-7-sqrt(17))/8$

$4x^2 = 2 - 7x$

$4x^2 + 7x - 2= 0$

The equation is of the form $color(blue)(ax^2+bx+c=0$ where:
$a=4, b=7, c= - 2$

The Discriminant is given by:

$Delta=b^2-4*a*c$

$= (7)^2-(4* 4 * (-2))$

$= 49 - 32 = 17$

The solutions are found using the formula
$x=(-b+-sqrtDelta)/(2*a)$

$x = ((-7)+-sqrt(17))/(2*4) = (-7+-sqrt(17))/8$

The solutions are:
$x= (-7+sqrt(17))/8$
$x= (-7-sqrt(17))/8$

How do you solve 4x² = 2 – 7x4x² = 2 – 7x?