How do you solve 4x2+8x+4=0?

1 Answer
Mar 14, 2018

The solution is x=1.

Explanation:

First, divide both sides by 4. Then, factor. Lastly, square root both sides and solve for x. Here's what that looks like:

4x2+8x+4=0

4x2+8x+44=04

x2+2x+1=0

x2+x+x+1=0

xx+x1+1x+11=0

x(x+1)+1(x+1)=0

(x+1)(x+1)=0

(x+1)2=0

(x+1)2=0

x+1=0

x=1

This is the answer. Hope this helped!