How do you solve $4 x^{2} - x^{3} = 0$ $4x^2 - x^3 =0$ ?

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Answer 1 · 2016-05-09T11:17:31

$x = 0, x = 4$ $x = 0, x = 4$

$4 x^{2} - x^{3} = 0$ $4x^2 - x^3 = 0$

$\Rightarrow x^{2} (4 - x) = 0$ $=> x^2(4 - x) = 0$

$\Rightarrow x^{2} = 0$ $=> x^2 = 0$
$\Rightarrow x = 0$ $=> x = 0$

$\Rightarrow 4 - x = 0$ $=> 4 - x = 0$

$\Rightarrow x = 4$ $=> x = 4$

How do you solve 4x2−x3=04x^2 - x^3 =0 ?