How do you solve #4x^2 + x = 60#?

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Answer 1 · 2015-06-11T15:34:59

#color(green)( x=15/4 , x = -4# are the solutions.

#4x^2 + x = 60#
#4x^2 + x - 60 = 0#

We can first factorise the expression and then find the solutions.

Factorising by splitting the middle term:

#4x^2 + x - 60 =4x^2 + (16x - 15x) - 60 #

# = 4x(x + 4) - 15(x+4)#

#(x+4)# is common to both terms.
# color(green)((4x-15)(x+4)# is the factorised form.

Upon equating #x# of both the terms with #0# we can obtain the solution.
#color(green)( x=15/4 , x = -4# are the solutions.