How do you solve $[(4x-3, 3y), (7,13)]=[(9,-15), (7,2z+1)]$ ?

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Answer 1 · 2017-01-28T12:21:35

We get that:
$x=3$
$y=-5$
$z=6$

Fot the two matrices to be equal each corresponding element must be equal.
So we need that:

$4x-3=9$
$3y=-15$
$7=7$
$13=2z+1$

from these equations we see that the third is ok while for the others (rearranging):

$x=12/4=3$
$y=-15/3=-5$
$z=12/2=6$

How do you solve [(4x-3, 3y), (7,13)]=[(9,-15), (7,2z+1)][(4x-3, 3y), (7,13)]=[(9,-15), (7,2z+1)]?