How do you solve 4x+6y=12 for x?

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Answer 1 · 2017-02-09T13:56:12

See the entire solution process below:

First, subtract $color(red)(6y)$ from each side of the equation to isolate the $x$ term while keeping the equation balanced:

$4x + 6y - color(red)(6y) = 12 - color(red)(6y)$

$4x + 0 = 12 - 6y$

$4x = 12 - 6y$

Now, divide each side by $color(red)(4)$ to solve for $x$ while keeping the equation balanced:

$(4x)/color(red)(4) = (12 - 6y)/color(red)(4)$

$(color(red)(cancel(color(black)(4)))x)/cancel(color(red)(4)) = (12 - 6y)/4$

$x = (12 - 6y)/4$

Or

$x = 12/4 - 6/4y$

$x = 3 - (2 xx 3)/(2 xx 2)y$

$x = 3 - (color(red)(cancel(color(black)(2))) xx 3)/(color(red)(cancel(color(black)(2))) xx 2)y$

$x = 3 - 3/2y$