How do you solve #-4x + 7= - 1( 2x - 3.5)#?

3 Answers
Jun 11, 2018

x=1.75

Explanation:

ok first ya wanna multiply #-1(2x-3.5)# which gets ya #-2x+3.5# (ya flipped the negatives to positives and vis versa) so at this point ya got #-4x+7=-2x+3.5# then ya wanna subtract 7 on both sides getting you #-4x=-2x-3.5# then add 2x on both sides so ya get #-2x=-3.5# so then ya wanna get x by it self so you divide -2 on both sides canceling the -2 on the left leaving you with #x=(-3.5)/(-2)# which ya simplify down to 1.75

if ya need more clarification go to https://www.symbolab.com/solver/step-by-step/-4x%2B7%3D-1%5Cleft(2x-3.5%5Cright) which tells ya it step by step

Jun 11, 2018

#x = 1.75#

Explanation:

#-4x + 7 = -1(2x - 3.5)#

Expand the right side by multiplying

#-4x + 7 = -2x + 3.5#

Move #x# to the right side (add #4x# to both sides)

#7 -4x + 4x = -2x + 3.5 + 4x#

#7 = 2x + 3.5#

Subtract #3.5# from both sides

#7 - 3.5 = 2x + 3.5 - 3.5#

#3.5 = 2x#

Divide both sides by #2#

#(2x)/2 = 3.5/2#

#x = 1.75#

Jun 11, 2018

See a solution process below:

Explanation:

First, expand the terms in parenthesis on the right side of the equation by multiplying each term within the parenthesis by the term outside the parenthesis.

#-4x + 7 = color(red)(-1)(2x - 3.5)#

#-4x + 7 = (color(red)(-1) xx 2x) + (color(red)(-1) xx -3.5)#

#-4x + 7 = -2x + 3.5#

Next, add #color(red)(4x)# and subtract #color(blue)(3.5)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#-4x + color(red)(4x) + 7 - color(blue)(3.5) = -2x + color(red)(4x) + 3.5 - color(blue)(3.5)#

#0 + 3.5 = (-2 + color(red)(4))x + 0#

#3.5 = 2x#

Now, divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#3.5/color(red)(2) = (2x)/color(red)(2)#

#1.75 = (color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2))#

#1.75 = x#

#x = 1.75#