How do you solve #5/2(4m+2)=35#?

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Answer 1 · 2015-11-06T17:15:46

#color(blue)(m=3#

#color(blue)((5/2)) * (4m+2) =35#

#4m+2 =cancel35 * color(blue)((2/cancel5)) #

#4m+2 =7 *2 #

#4m+2 =14 #

#4m =14-2 #

#4m =12 #

#m=12/4#

#color(blue)(m=3#