How do you solve $5 \cdot 6^{3 m} = 20$ $5*6^(3m)=20$ ?

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How do you solve $5 \cdot 6^{3 m} = 20$ $5*6^(3m)=20$ ?

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Answer 1 · 2016-12-26T08:28:37

$m = 0.2579$ $m=0.2579$

Explanation:

$5 \cdot 6^{3 m} = 20$ $5*6^(3m)=20$
$\Rightarrow 6^{3 m} = \frac{20}{5} = 4$ $=> 6^(3m)=20/5=4$
take log of both sides:
${log 6}^{3 m} = log 4$ $log6^(3m)=log4$
$\Rightarrow 3 m log 6 = log 4$ $=> 3mlog6=log4$
$\Rightarrow 3 m = \frac{log 4}{log 6} = 0.7737$ $=> 3m=log4/log6=0.7737$
$\Rightarrow m = \frac{0.7737}{3} = 0.2579$ $=> m=0.7737/3=0.2579$

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How do you solve $5 \cdot 6^{3 m} = 20$ $5*6^(3m)=20$ ?

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