How do you solve $-5( 8b + 8) = - 160$ ?

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Answer 1 · 2016-11-19T13:35:27

$b = 3$

Step 1) Expand the terms within parenthesis:

$(-5*8b) + (-5*8) = -160$

$-40b - 40 = -160$

Step 2) Solve for $b$ while keeping the equation balanced:

$-40b - 40 + 40 = -160 + 40$

$-40b - 0 = -120$

$-40b = -120$

$(-40b)/-40 = -120/(-40)$

$1b = 3$

$b = 3$

How do you solve -5( 8b + 8) = - 160-5( 8b + 8) = - 160?