How do you solve $-5< \frac{8x - 5}{6} < 7$ ?

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Answer 1 · 2018-06-05T05:54:46

Undo the operations surrounding $x$ by applying the inverses to both sides in the reverse order.

Multiply all sides by $6$ :

$-30 < 8x - 5 < 42$

Add $5$ :

$-25 < 8x < 47$

Divide all sides by $8$ :

$-25/8 < x < 47/8$

How do you solve -5< \frac{8x - 5}{6} < 7-5< \frac{8x - 5}{6} < 7?