How do you solve #5(x+2)=12+x#?

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Answer 1 · 2016-02-23T18:30:35

#x=1/2#

#5 (x+2) = 12 +x#

#5 xx (x ) + 5 xx (2) = 12 +x#

#5 x + 10 = 12 +x#

#5 x -x = 12 -10#

#4x = 2#

#x= 2/4#

#x=1/2#