How do you solve $5 - x^{2} = 20$ $5 - x^2 = 20$ ?

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Answer 1 · 2017-06-01T01:29:28

$x = - 3.873$ $x = -3.873$

$5 - x^{2} = 20$ $5-x^2 = 20$

$- x^{2} = 20 - 5$ $-x^2 = 20-5$

$- x^{2} = 15$ $-x^2 = 15$

$- x = \sqrt{15}$ $-x = sqrt15$

$- x = 3.873$ $-x = 3.873$

$x = - 3.873$ $color(blue)(x = -3.873$

We can now prove our answer by substituting $x$ $x$ for $- 3.873$ $-3.873$

$5 - x^{2} = 20$ $5-x^2 = 20$

$5 - - {3.873}^{2} = 20$ $5- -3.873^2 = 20$

$5 + {3.873}^{2} = 20$ $5 + 3.873^2 = 20$

$5 + 15 = 20$ $5 + 15 = 20$

How do you solve 5−x2=205 - x^2 = 20?