How do you solve $5 {(x + 3)}^{2} + 116 = 361$ $5(x+3)^2+116=361$ ?

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Answer 1 · 2017-07-18T16:26:49

$x = 4 or x = - 10$ $color(blue)(x=4 or x=-10$

$5 {(x + 3)}^{2} + 116 = 361$ $5(x+3)^2+116=361$

$:.5(x+3)^2=245$

$:.(x+3)^2=49$

$:.x+3=sqrt49$

$:.x=-3+-sqrt49$

$:.color(blue)(x=-3+7=4$

$:.color(blue)(or x=-3-7=-10$

substitute $color(blue)(x=4$

$:.5(color(blue)(4))+3)^2+116=361$

$:.5(7^2)+116=361$

$:.5(49)+116=361$

$:.245+116=361$

$color(blue)(361=361$

substitute $color(blue)(x=-10$

$:.5(color(blue)((-10))+3)^2+116=361$

$:.5(-7)^2+116=361$

$:.5(49)+116=361$

$:.245+116=361$

$color(blue)(361=361$

How do you solve 5(x+3)^2+116=3615(x+3)2+116=3615(x+3)^2+116=361?