How do you solve $5 (x - 3) + 2 (3 - x) = 12$ $5(x-3)+2(3-x)=12$ ?

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How do you solve $5 (x - 3) + 2 (3 - x) = 12$ $5(x-3)+2(3-x)=12$ ?

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Answer 1 · 2016-02-21T17:56:21

$x = 7$ $x=7$

Explanation:

$5 (x - 3) + 2 (3 - x) = 12$ $5(x−3)+2(3−x)=12$

$5 \times (x) + 5 \times (- 3) + 2 \times (3) + 2 \times (- x) = 12$ $5 xx (x) + 5 xx (−3)+2 xx (3) + 2 xx (−x)=12$

$5 x - 15 + 6 - 2 x = 12$ $5x -15 + 6 -2x=12$

$5 x - 9 - 2 x = 12$ $5x -9 -2x=12$

$3 x - 9 = 12$ $3x -9 =12$

$3 x = 12 + 9$ $3x =12 +9$

$3 x = 21$ $3x =21$

$x = \frac{21}{3}$ $x =21/3$

$x = 7$ $x=7$

Answer 2 · 2016-02-23T14:22:10

$x = 7$ $x=7$

Explanation:

$5 (x - 3) + 2 (3 - x) = 12$ $color(blue)(5(x-3)+2(3-x)=12$

Use distributive property $a (b + c) = a b + a c$ $color(red)(a(b+c)=ab+ac$

$\to (5 x - 15) + (6 - 2 x) = 12$ $rarr(5x-15)+(6-2x)=12$

Remove the brackets

$\to 5 x - 15 + 6 - 2 x = 12$ $rarr5x-15+6-2x=12$

$\to 3 x - 9 = 12$ $rarr3x-9=12$

Add $9$ $9$ both sides

$\to 3 x = 12 + 9$ $rarr3x=12+9$

$\to 3 x = 21$ $rarr3x=21$

$\Rightarrow x = \frac{21}{3} = 7$ $rArrcolor(green)(x=21/3=7$

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How do you solve $5 (x - 3) + 2 (3 - x) = 12$ $5(x-3)+2(3-x)=12$ ?

2 Answers

Explanation:

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How do you solve $5 (x - 3) + 2 (3 - x) = 12$ $5(x-3)+2(3-x)=12$ ?