Question

How do you solve `5(x-3)^2 = 45`?

Answer 1

`x =6 or x=0`

Explanation:

Divide both sides by 5

`=>` `(x-3)^2=9`

Square root both sides

`=>` `x-3=\pm3`

Add 3 to both sides

`=>` `x =6 or x=0`