How do you solve # 5 |x - 3| >=20#? Algebra Linear Inequalities and Absolute Value Absolute Value Inequalities 1 Answer Binayaka C. Aug 30, 2016 #x>=7 or x<= -1#. In interval notation, solution is #(-oo , -1] uu [7, +oo)# Explanation: #5|x-3|>=20 or |x-3|>=4 :. x-3>=4 or x>=7# OR #5|x-3|>=20 or |x-3|>=4 :. x-3<= -4 or x<= -1# In interval notation solution is #(-oo , -1] uu [7, +oo)#[Ans] Answer link Related questions How do you solve absolute value inequalities? When is a solution "all real numbers" when solving absolute value inequalities? How do you solve #|a+1|\le 4#? How do you solve #|-6t+3|+9 \ge 18#? How do you graph #|7x| \ge 21#? Are all absolute value inequalities going to turn into compound inequalities? How do you solve for x given #|\frac{2x}{7}+9 | > frac{5}{7}#? How do you solve #abs(2x-3)<=4#? How do you solve #abs(2-x)>abs(x+1)#? How do you solve this absolute-value inequality #6abs(2x + 5 )> 66#? See all questions in Absolute Value Inequalities Impact of this question 1596 views around the world You can reuse this answer Creative Commons License