How do you solve #5( z + 6) - 8z = 20+ 6( 8- z )#?

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Answer 1 · 2018-07-07T13:30:26

#z=38/3#

Expanding we get

#5z+30-8z=20+48-6z#
combining like Terms

#-3z+30=68-6z#
adding #6z# and subtracting #30#
we obtain

#3z=38#
so #z=38/3#

Answer 2 · 2018-07-07T15:10:48

#z=38/3#

Let's start by distributing the #5# to the parenthesis on the left, and the #6# to the parenthesis on the right. We get

#5z+30-8z=20+48-6z#

Let's combine the #z# terms we have on the left, and the constants we have on the right. We now have:

#-3z+30=68-6z#

Remember, we just want a #z# on the left side. We can next achieve this by subtracting #30# from both sides. We get

#-3z=38-6z#

Next, let's add #6z# to both sides to get

#3z=38#

And our last step, dividing both sides by #3# to get

#z=38/3#

Hope this helps!