How do you solve $5 (z + 6) - 8 z = 20 + 6 (8 - z)$ $5( z + 6) - 8z = 20+ 6( 8- z )$ ?

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Answer 1 · 2018-07-07T13:30:26

$z = \frac{38}{3}$ $z=38/3$

Expanding we get

$5 z + 30 - 8 z = 20 + 48 - 6 z$ $5z+30-8z=20+48-6z$
combining like Terms

$- 3 z + 30 = 68 - 6 z$ $-3z+30=68-6z$
adding $6 z$ $6z$ and subtracting $30$ $30$
we obtain

$3 z = 38$ $3z=38$
so $z = \frac{38}{3}$ $z=38/3$

Answer 2 · 2018-07-07T15:10:48

$z = \frac{38}{3}$ $z=38/3$

Let's start by distributing the $5$ $5$ to the parenthesis on the left, and the $6$ $6$ to the parenthesis on the right. We get

$5 z + 30 - 8 z = 20 + 48 - 6 z$ $5z+30-8z=20+48-6z$

Let's combine the $z$ $z$ terms we have on the left, and the constants we have on the right. We now have:

$- 3 z + 30 = 68 - 6 z$ $-3z+30=68-6z$

Remember, we just want a $z$ $z$ on the left side. We can next achieve this by subtracting $30$ $30$ from both sides. We get

$- 3 z = 38 - 6 z$ $-3z=38-6z$

Next, let's add $6 z$ $6z$ to both sides to get

$3 z = 38$ $3z=38$

And our last step, dividing both sides by $3$ $3$ to get

$z = \frac{38}{3}$ $z=38/3$

Hope this helps!

How do you solve 5(z+6)−8z=20+6(8−z)5( z + 6) - 8z = 20+ 6( 8- z )?