How do you solve $5b-2b^2+18=0$ ?

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Answer 1 · 2016-04-10T20:53:13

$b=-2$
or
$b=9/2=4 1/2$

$5b-2b^2+1=0$

$rarr 2b^2-5b-18=0$

$rarr (2b-9)(b+2)=0$

${: ((2b-9=0),color(white)("XX")orcolor(white)("XX"),(b+2=0)), (rarr b=9/2,,rarrb=-2) :}$

How do you solve 5b-2b^2+18=05b-2b^2+18=0?