How do you solve $5e^(3t) = 8e^(2t)$ ?

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Answer 1 · 2016-06-14T08:36:31

$t = log_e(8/5)$

After some trasformations we get at

$e^{3t}/(e^{2t}) = 8/5$ or $e^t = 8/5$

Solving for $t$ we have

$t log_e e = t xx 1 = t = log_e(8/5)$

How do you solve 5e^(3t) = 8e^(2t)5e^(3t) = 8e^(2t)?