How do you solve $(5n - 1) (n+1) = 0$ by factoring?

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Answer 1 · 2015-08-17T06:39:46

The solutions are
$color(blue)(n=1/5, n=-1$

$(5n−1)(n+1)=0$
This is the factorised form for the equation $5n^2+4n-1=0$

Since we already have the factors we simply equate them to the R.H.S:
$5n−1=0, color(blue)(n=1/5$

$n+1=0, color(blue)(n=-1$

How do you solve (5n - 1) (n+1) = 0(5n - 1) (n+1) = 0 by factoring?