How do you solve $5 p^{2} - 15 p = 0$ $5p^2-15p=0$ ?

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Answer 1 · 2016-09-11T12:46:23

$p = 0, 3$ $p = 0, 3$

We have: $5 p^{2} - 15 p = 0$ $5 p^(2) - 15 p = 0$

Let's factorise the equation:

$\Rightarrow 5 p (p - 3) = 0$ $=> 5 p (p - 3) = 0$

As we now have a product that is equal to zero, either one of the multiples must be equal to zero:

$\Rightarrow 5 p = 0$ $=> 5 p = 0$

$\Rightarrow p = 0$ $=> p = 0$

or

$\Rightarrow p - 3 = 0$ $=> p - 3 = 0$

$\Rightarrow p = 3$ $=> p = 3$

Therefore, the solutions to the equation are $p = 0$ $p = 0$ and $p = 3$ $p = 3$ .

Answer 2 · 2016-09-11T12:50:18

$5p²-15p=0$
$5p(p-3)=0$
$5p=0, p-3=0$
$p=0/5, p=0+3$
$p=0, p=3$
$S.S{0 or 3}$

How do you solve 5p^2-15p=05p2−15p=05p^2-15p=0?