How do you solve $5 q^{2} + 8 w = 80$ $5q^2+8w=80$ ?

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How do you solve $5 q^{2} + 8 w = 80$ $5q^2+8w=80$ ?

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Answer 1 · 2015-08-26T11:11:55

$w = 10 - \frac{5}{8} q^{2}$ $w=10-5/8q^2$
or
$q = \pm 2 \sqrt{\frac{20 - 4 w}{5}}$ $q=+-2sqrt((20-4w)/5)$

Explanation:

Since you have one equation with two variables,
the best you can do is rewrite the equations giving one of the variables as an expression of the other.

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How do you solve $5 q^{2} + 8 w = 80$ $5q^2+8w=80$ ?

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