How do you solve 5r+3=2r2?

2 Answers
Aug 8, 2018

r1=12 and r2=3

Explanation:

5r+3=2r2

2r25r3=0

(2r+1)(r3)=0

So r1=12 and r2=3

Aug 8, 2018

r=12 or r=3

Explanation:

rearrange into standard form ;ax2+bx+c=0;a0

subtract 5r+3 from both sides

2r25r3=0

factor using the a-c method

the factors of the product 2×3=6

which sum to 5 are 6 and +1

split the middle term using these factors

2r26r+r3=0factor by grouping

2r(r3)+1(r3)=0

take out the common factor (r3)

(r3)(2r+1)=0

equate each factor to zero and solve for r

2r+1=0r=12

r3=0r=3