Question

How do you solve `5t^2=25t`?

Answer 1

`t=0,t=5`

Explanation:

Collect terms on left side of equation thus equating to zero.

subtract 25t from both sides.

`5t^2-25t=cancel(25t)cancel(-25t)`

`rArr5t^2-25t=0`

Take out a common factor of 5t

`5t(t-5)=0`

We now have a product of factors equal to zero.

`"Thus " 5t=0rArrt=0`

`"or " t-5=0rArrt=5`