How do you solve $5x^2-2x-6=-3x^2+6x$ ?

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Answer 1 · 2017-06-27T10:17:01

$x=-1/2$ , or $x=1/2$

First, let's add $3x^2$ to both sides

$8x^2-2x-6=6x$

Then, subtract $6x$ from both sides

$8x^2-8x-6=0$

Divide the entire equation by $2$

$4x^2-4x-3=0$

Factorise

$(2x+1)(2x-3)=0$

Set each factor equal to $0$

$2x+1=0$
$2x=-1$

$x=-1/2$

$2x-3=0$
$2x=3$
$x=1/2$

Here is the graph

graph{4x^2-4x-3 [-3.08, 3.08, -1.54, 1.54]}

How do you solve 5x^2-2x-6=-3x^2+6x5x^2-2x-6=-3x^2+6x?