How do you solve $|5x + 2| < 7$ ?

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Answer 1 · 2016-03-03T17:08:44

$5x+2<7 and 5x+2> -7,5x<5->x<1 and 5x > -9->x > -9/5$
$(-9/5) < x<1$

Use the definition of absolute value of x to solve. That is, $|x|=x if x>=0, and -x if x<0$ . Then solve for x

How do you solve |5x + 2| < 7|5x + 2| < 7?