How do you solve $5 y^{2} - 180 = 0$ $5y^2-180=0$ ?

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Answer 1 · 2016-03-18T19:18:40

Factor this as follows

$5 y^{2} - 180 = 0 \Rightarrow 5 \cdot (y^{2} - 36) = 0 \Rightarrow 5 \cdot (y - 6) (y + 6) = 0$ $5y^2-180=0=>5*(y^2-36)=0=>5*(y-6)(y+6)=0$

From the last equation the solutions are

$y_{1} = 6$ $y_1=6$ and $y_{2} = - 6$ $y_2=-6$

How do you solve 5y2−180=05y^2-180=0?