How do you solve $5 y^{2} = 30 y$ $5y^2=30y$ ?

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Answer 1 · 2018-07-14T16:12:20

$y = 0$ $y=0$ or $y = 6$ $y=6$

Writing your equation in the form
$5 y (y - 6) = 0$ $5y(y-6)=0$
so we get

$y = 0$ $y=0$ or $y = 6$ $y=6$

Answer 2 · 2018-07-14T16:14:14

$y = 0$ $y=0$ and $y = 6$ $y=6$

We have a second-degree term, so this is beginning to look like a quadratic. Let's subtract $30 y$ $30y$ from both sides to find the zeroes:

$5 y^{2} - 30 y = 0$ $5y^2-30y=0$

We can factor a $5 y$ $5y$ out, and we get

$5 y (y - 6) = 0$ $5y(y-6)=0$

Setting both factors equal to zero, we get

$y = 0$ $y=0$ and $y = 6$ $y=6$

Hope this helps!

How do you solve 5y2=30y5y^2=30y?