Question

How do you solve `5y-5=10`?

Answer 1

`y=3`

Explanation:

`"isolate "5y" by adding 5 to both sides of the equation"`

`5ycancel(-5)cancel(+5)=10+5`

`rArr5y=15`

`"divide both sides by 5"`

`(cancel(5) y)/cancel(5)=15/5`

`rArry=3`

`(5xx3)-5=15-5=10larr"Check"`