How do you solve $-6 + |2x – 4| = -3$ ?

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Answer 1 · 2016-01-27T13:38:13

$x={1/2,7/2}$

Absolute value is the distance between a value and 0 on the number line
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So, the distance should be always a positive integer

$-6+|\2x-4|=-3$

$|\2x-4|=6-3=3$

This equation is possible because the absolute value is a positive integer.

Assume 2 values:

$2x-4=3$

$2x-4=-3$

Solve for the first equation:

$2x-4=3$

$2x=3+4=7$

$2x=7$

$x=7/2$

So, the first value of $x$ is $7/2$

Now solve for second equation:

$2x-4=-3$

$2x=4-3=1$

$2x=1$

$x=1/2$

So, $x={1/2,7/2}$

How do you solve -6 + |2x – 4| = -3-6 + |2x – 4| = -3?