How do you solve #-6- 4k ^ { 2} = - 51#?
1 Answer
May 13, 2018
Explanation:
#"isolate "k^2" by adding 6 to both sides and dividing by "-4#
#rArr-4k^2=-51+6=-45#
#rArrk^2=(-45)/(-4)=45/4#
#color(blue)"take the square root of both sides"#
#sqrt(k^2)=+-sqrt(45/4)larrcolor(blue)"note plus or minus"#
#rArrk=+-(3sqrt5)/2#
