How do you solve $6 (6 x + 9) - 3 = 9 x + 6$ $6( 6x + 9) - 3= 9x + 6$ ?

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How do you solve $6 (6 x + 9) - 3 = 9 x + 6$ $6( 6x + 9) - 3= 9x + 6$ ?

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Answer 1 · 2017-07-20T12:54:18

Distribute across the parenthesis and solve for $x$ $x$

$x = - \frac{5}{3}$ $x = -5/3$

Explanation:

$6 (6 x + 9) - 3 = 9 x + 6$ $6(6x +9) -3 = 9x+6$

$36 x + 54 - 3 = 9 x + 6$ $36 x + 54 -3 =9x+6" "$ so now combine like terms

$36 x + 51 = 9 x + 6$ $36x +51 = 9x + 6" "$ subtract $9 x and 51$ $9x and 51$ from both sides

$36 x - 9 x + 51 - 51 = 9 x - 9 x + 6 - 51$ $36x - 9x + 51 -51 = 9x -9x + 6 - 51" "$ gives

$27 x = - 45$ $27x = -45" "$ dividing both sides by 27 gives

$\frac{27 x}{27} = \frac{- 45}{27}$ $(27x)/27 = (-45)/27$ gives

$x = - \frac{5}{3}$ $x = -5/3$

$x = - 1 \frac{2}{3}$ $x = - 1 2/3$

Answer 2 · 2017-07-21T18:35:23

$6 (6 x + 9) - 3 = 9 x + 6$ $6(6x+9)-3=9x+6$
$36 x + 54 - 3 = 9 x + 6$ $36x+54-3=9x+6$
$36 x - 9 x = - 54 + 3 + 6$ $36x-9x=-54+3+6$
$27 x = - 54 + 9$ $27x=-54+9$
$27 x = - 45$ $27x=-45$
$x = \frac{- 45}{27}$ $x=frac(-45) 27$
Both are divisible by 9
$x = \frac{- 5}{3}$ $x=frac(-5) 3$

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How do you solve $6 (6 x + 9) - 3 = 9 x + 6$ $6( 6x + 9) - 3= 9x + 6$ ?

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