How do you solve $| 6 - y | = 8$ $|6-y|=8$ ?

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Answer 1 · 2017-08-03T10:59:16

$y_{1}$ $y_1$ = -2
$y_{2}$ $y_2$ = 14

First of all separate the two absolute equations as if they were two separate equations (one positive and one negative)

6- $y$ $y$ =8
6- $y$ $y$ =-8

Then, you solve equations. Solve the first one

$\Rightarrow - y = 8 - 6 \Rightarrow - y = 2 \Rightarrow y = - 2$ $=> -y = 8-6 => -y = 2 => y = -2$

Then, the second one :

$\Rightarrow - y = - 8 - 6 \Rightarrow - y = - 14 \Rightarrow y = 14$ $=> -y = -8-6 => -y = -14 => y = 14$

So the two solutions are

$y_{1} = - 2$ $y_1 = -2$
and
$y_{2} = 14$ $y_2 = 14$

How do you solve |6-y|=8|6−y|=8|6-y|=8?